number system Model Questions & Answers, Practice Test for ibps clerk prelims

Answer: (d)

We know that, If the difference between the sum of digits at even places and sum of digits at odd places is (0) or multiple of 11, then the number is divisible by 11.

From options,

(a) 45678940

Sum of even places = 5 + 7 + 9 + 0 = 21

Sum of odd palaces = 4 + 6 + 8 + 4 = 22

Their difference = 22 – 21 = 1 ≠ 0

(b) 54857266

Sum of even places = 4 + 5 + 2 + 6 = 17

Sum of odd palaces = 5 + 8 + 7 + 6 = 26

Their difference = 26 – 17 = 9 ≠ 0

(c) 87524398

Sum of even places = 7 + 2 + 3 + 8 = 20

Sum of odd palaces = 8 + 5 + 4 + 9 = 26

Their difference = 26 – 20 = 6 ≠ 0

(d) 93455120

Sum of even places = 3 + 5 + 1 + 0 = 9

Sum of odd palaces = 9 + 4 + 5 + 2 = 20

Difference = 20 – 9 = 11

It is divisible by 11.

Answer: (b)

Sum to be collected from 54 students

= 60×54 = 3240 Rs.

Sum collected from 45 students

= 60 × 45 = 2700 Rs.

Difference = 3240 - 2700 = 540 Rs.

∴ Additional amount to be paid by each student

= $540/45$ = Rs. 12

Answer: (a)

Let the number be x.

Then, as per the operation undertook by the student, we have

${x + 12}/6$ ⇒ x = 660

Hence, the correct answer = $660/6 + 12 = 122$

Answer: (a)

When a number n is divided by 4 then remainder is 3.

Now, the number is double then remainder is also double.

So, remainder = 6

But remainder never greater than its divisor.

So, remainder = 6 – 4 = 2

Answer: (b)

Here 7, and 3 both are repeat its unit digit after four times.

= $7^(4 × 100 + 2) + 3^(4 × 100 + 2)$

= $7^{4 × 100} × 7^2 + 3^{4 × 100} × 3^{2}$

= 9 + 9 = 18

So, its unit digit = 8